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That is to say that the LEDs all come on at a much smaller turn of the potentiometer.
Most people use “low” to refer to either a lower voltage, or a lower position on the diagram. You might want to edit to explain your answer a bit more. Per AN’d datasheetPin 8 is the signal input pin, and it’s the internal Op amp’s positive input.
Home Questions Tags Users Unanswered. Pin 8 accepts a positive input voltage. However, if that’s the case, I can’t explain why reversing the capacitor doesn’t work, unless the actual polarity of the capacitor is backwards from what you think it is. I’m not following you. Can someone explain what the reversed capacitor is doing here? This circuit will light the LEDs as the input voltage on pin 8 increases relative to pin 7. The potentiometer is clear, but the 2.
AN 데이터시트(PDF) – Panasonic Semiconductor
Very confusing terminology, since the inverting input can have a higher voltage than the noninverting input. This makes sense, but why not a diode?
I know the correct names, but I conversely find “inverting” and “noninverting” confusing when dealing with comparators, since those terms make more sense when dealing with op-amps. It appears to be reversed. It’s the DC bias determine the polarity. By using our site, you acknowledge that you have read and understand our Cookie PolicyDatwsheet Policyand our Terms of Service. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies.
To be clear, removing the capacitor doesn’t light up the LEDs all at once. There is dstasheet no discharge path with your arrangement. Pin 8 is the signal input datasyeet, and it’s the internal Op amp’s positive input. I’m not reading it that way. As displayed, the LEDs go from fully off to fully on over roughly the entire turn range of the potentiometer.
(PDF) AN6884 Datasheet download
Post as an688 guest Name. Sign up using Email and Password. Pin 7 is the output of the internal amplifier, and pin 8 is its input, designed to accept a low-level AC input 57 mV for a 0-dB indication.
Sign up or log in Sign up using Google. That means there is a small current flow out from the pin. That’s clear, because the input in my test circuit is DC. Email Required, but never shown. How does doing anything to pin 7 or pin 8 affect that?
Setting 7 higher than ground biases the low side of the comparators, allowing them to turn on with a lower output from the amp.
Your description doesn’t agree with that in the datasheet. So it determines the DC bias of the block capacitor’s polarity. Post Your Answer Discard By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these an68844.
By “low side”, you’re referring to the inverting inputs of the comparators. There’s still a much shorter range over which a varying number of LEDs come on. It just shortens the range of turn over which the potentiometer works.
Per AN’d datasheet. Vref is the high side of the 5 LED comparators in the datasheet block diagram.
It sounds like you’re trying to drive this circuit with a signal that includes a considerable DC bias, which explains why all of the LEDs light up right away when you remove short out the capacitor.
Passing Vin through a reverse capacitor seems to be potentially more prone to failure. If I “correct” the datashset, the circuit does not work at all. Placing it at a datashheet voltage within the datasheet’s max specified V will both lower the amplification and raise the lower rail of the comparators in the block diagram.
Ah6884 LED pins connect to the negative side of the LEDs, and the pins go low when the output of the internal amp goes above Vref dropped by voltage dividing resistors at each comparator.